4x^2+100x+49=0

Solution for 4x^2+100x+49=0 equation:

4x^2+100x+49=0

a = 4; b = 100; c = +49;
Δ = b2-4ac
Δ = 1002-4·4·49
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-96}{2*4}=\frac{-196}{8}
=-24+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+96}{2*4}=\frac{-4}{8}
=-1/2
$